document.write( "Question 1182597: ESTIMATING THE POPULATION MEAN WITH UNKNOWN VARIANCE USING A SMALL SAMPLE\r
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document.write( "The mean length 𝜇 of time consumed in online classes per day of Senior High School students would have to be estimated. A sample of 20 students had a mean of 3.5 hours a day with a sample standard deviation of 0.8 hour. Find the 95 % confidence interval for the 𝜇. \n" );
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Algebra.Com's Answer #813634 by Theo(13342) You can put this solution on YOUR website! the sample mean is equal to 3.5 hours. \n" ); document.write( "the sample standard deviation is equal to .8 hours. \n" ); document.write( "the sample size is 20.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t-score would be used with 19 degrees of freedom is what i think. \n" ); document.write( "at 95% confidence level, the two tail critical t-score with 19 degrees of freedom would be equal to plus or minus 2.093.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "19 degrees of freedom is because the sample size is 20.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the standard error would be equal to .8 / sqrt(20) = .1789. \n" ); document.write( "that's the standard deviation of the sample divided by the square root of the sample size.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the t-score formula becomes plus or minus 2.093 = (x - 3.5) / .1789\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = .1789 * 2.093 + 3.5 on the high side and x = .1789 * -2.093 + 3.5 on the low side.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x will be equal to 3.8744377 on the high side. \n" ); document.write( "x will be equal to 3.1255623 on the low side.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your confidence interval is from 3.1256 on the low side to 3.8744 on the high side when the solution is rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph of the critical t-score would look like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you need to find the standard error and use the t-score formula to find the raw scores from the t-scores.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i did that above.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "standard error = standard deviation of sample divided by square root of sample size.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t-score formula is t = (x = m) / s \n" ); document.write( "t is the t-score \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard error\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |