document.write( "Question 1183336: A fast food restaurant specializes in hame sandwiches. A customer may choose to add any of the following: mayonnaise, mustard, lettuce, tomato, or cheese. How many different ham sandwich combinations are possible?
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document.write( "(Note: The answer is 32, which is solved by doing 2^5; However, I do not understand the logic and reasoning behind simply getting 2 and raising it to the power of 5 rather than treating the problem as a series of multiple permutations of 5!*4!*3!*2!*1!*0!) \n" );
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Algebra.Com's Answer #813608 by ikleyn(52798)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'd like to add my 2 cents regarding your note, where you write for a series of 5 permutations \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 5!*4!*3!*2!*1!*0!\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is written incorrectly. The number of permutations of 5 items is \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 5! = 5*4*3*2*1 = 120.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Be accurate, when you write Math ( ! )\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Every word and every symbol matters . . . \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |