document.write( "Question 1183318: i).find the surface area of a rectangular glass block whose volume is
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Algebra.Com's Answer #813605 by Edwin McCravy(20056)\"\" \"About 
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i).find the surface area of a rectangular glass block whose volume is
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document.write( "That glass \"block\" which is is 72cm long and 48cm wide, is\r\n" );
document.write( "less than half a centimeter high!\r\n" );
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document.write( "So it's not really a glass block.  It's a sheet of glass to\r\n" );
document.write( "be installed in a window as a window-pane!\r\n" );
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document.write( "So we wouldn't call the 0.4410 cm \"the height\", but rather,\r\n" );
document.write( "\"the THICKNESS\" of the window pane.\r\n" );
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document.write( "The surface area is the total area of the front and back\r\n" );
document.write( "surfaces which is two times this area:\r\n" );
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document.write( "A = LW\r\n" );
document.write( "A = (72 cm)(48 cm)\r\n" );
document.write( "A = 3456 cm2\r\n" );
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document.write( "Twice that is  \r\n" );
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document.write( "Total area of front and back = 6912 cm2\r\n" );
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document.write( "The area of the left and right edges is twice this area:\r\n" );
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document.write( "A = LW     (The width is the thickness)\r\n" );
document.write( "A = (72 cm)(0.4410 cm)\r\n" );
document.write( "A = 31.752 cm2\r\n" );
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document.write( "Twice that is 63.504 cm2\r\n" );
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document.write( "The area of the top and bottom edges is twice this area:\r\n" );
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document.write( "A = LW     (The width is the thickness)\r\n" );
document.write( "A = (48 cm)(0.4410 cm)\r\n" );
document.write( "A = 21.168 cm2\r\n" );
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document.write( "Twice that is 42.336 cm2\r\n" );
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document.write( "Add all of it up:\r\n" );
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document.write( "Total area of front and back = 6912 cm2\r\n" );
document.write( "Total area of left and right long edges = 63.504 cm2\r\n" );
document.write( "Total area of top and bottom short edges = 42.336 cm2\r\n" );
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document.write( "Total surface area = 7017.84 cm2\r\n" );
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document.write( "Edwin
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