document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1183328>Question 1183328</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the height of a right circular cone is decreased by 8 percent by what percent must the radius of the base be decreased so that the volume of the cone is decreased by 15 percent? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #813584 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=813584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the height of a right circular cone is decreased by 8 percent by what percent must the radius of the base be decreased so that the volume of the cone is decreased by 15 percent?<BR>\n" );
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document.write( "8% reduction = .92h<BR>\n" );
document.write( "15% reduction = .85v<BR>\n" );
document.write( "let a = reduced amt multiplier time the radius \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A%28ar%29%5E2%2A.92h ALIGN=MIDDLE  ALT=\"pi%2A%28ar%29%5E2%2A.92h\"   DISABLED_style= \"max-width:90%; height:auto;\" > = .85(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2%2Ah ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" >)<BR>\n" );
document.write( "multiply both sides by 3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A%28a%5E2r%5E2%29%2A.92h ALIGN=MIDDLE  ALT=\"pi%2A%28a%5E2r%5E2%29%2A.92h\"   DISABLED_style= \"max-width:90%; height:auto;\" > = .85(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2%2Ah ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" >)<BR>\n" );
document.write( "divide both side by pi*r^2*h<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2A.92+=+.85 ALIGN=MIDDLE  ALT=\"a%5E2%2A.92+=+.85\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+=+.85%2F.92 ALIGN=MIDDLE  ALT=\"a%5E2+=+.85%2F.92\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28.924%29 ALIGN=MIDDLE  ALT=\"sqrt%28.924%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = .9612 times the radius, therefore<BR>\n" );
document.write( "Radius has to be reduced by 3.88%\r<BR>\n" );
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document.write( " </SPAN>\n" );
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