document.write( "Question 1182681: Ahmad is fishing in a new pond stocked with 5 catfish, 7 seabass, and 8 tilapia. Ahmad's objective is to catch a Catfish. ifa catfish is not caught. he releases it into the pond and the process is repeated until a catfish is caught. the probability that the second fish caught is seabass is 21/80. find the probability that either the second fish caught is seabass or the forth fish cought is catfish. \n" ); document.write( "
| Algebra.Com's Answer #813580 by robertb(5830)     You can put this solution on YOUR website! P((2nd fish is seabass) U (4th fish is catfish)) = \n" ); document.write( "P(2nd fish is seabass) + P(4th fish is catfish) -P((2nd fish is seabass) AND (4th fish is catfish)). \n" ); document.write( "Now P(2nd fish is seabass) = 21/80, while P(4th fish is catfish) = \n" ); document.write( "(Remember the non-catfish caught is thrown back to the pond until a catfish is caught).\r \n" ); document.write( "\n" ); document.write( "==>P(2nd fish is seabass) + P(4th fish is catfish) - P((2nd fish is seabass) AND (4th fish is catfish)) = 21/80 + 27/256 - 1575/32000 = \n" ); document.write( "\n" ); document.write( "***P((2nd fish is seabass) AND (4th fish is catfish)) = P(s,s,s,c) + P(s,s,t,c) \n" ); document.write( "+ P(t,s,s,c) + P(t,s,t,c) = 1575/32,000.*** \n" ); document.write( " |