document.write( "Question 1183312: A triangular piece of wood has side lengths 14 cm, 19 cm and 20 cm. The angle between the 14 cm and 19
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Algebra.Com's Answer #813560 by ikleyn(52805)\"\" \"About 
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\n" ); document.write( "A triangular piece of wood has side lengths 14 cm, 19 cm and 20 cm. The angle between the 14 cm and
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document.write( "Use the cosine law \r\n" );
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document.write( "    20^2 = 14^2 + 19^2 - 2*14*19*cos(a).\r\n" );
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document.write( "where \"a\" is the sough angle between the 14 cm and 19 cm sides.  It gives\r\n" );
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document.write( "    cos(a) = \"%2814%5E2+%2B+19%5E2+-+20%5E2%29%2F%282%2A14%2A19%29\" = 0.295113.\r\n" );
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document.write( "Hence,  a = arccos(0.295113) = 1.271 radians = 72.8 degrees   (rounded as requested).\r\n" );
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