document.write( "Question 1183154: A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than examining the records for all students, the dean randomly selected 200 students and finds that 118 of them are receiving financial aid. Use a 90% confidence interval to estimate the true proportion of students who receive financial aid. \n" ); document.write( "
Algebra.Com's Answer #813545 by Boreal(15235)\"\" \"About 
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p hat=0.59
\n" ); document.write( "90% half-interval is z(0.95)*sqrt(p*(1-p)/n)
\n" ); document.write( "=1.645*sqrt(0.59*0.41/200)
\n" ); document.write( "=0.0572
\n" ); document.write( "the 90%CI is (0.533, 0.647)
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