document.write( "Question 1183251: Outside temperature over a day can be modelled as a sinusoidal function. Suppose you know the high temperature for the day is 90 degrees and the low temperature of 80 degrees occurs at 6 AM. Assuming t is the number of hours since midnight, find an equation for the temperature, D, in terms of t.\r
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Algebra.Com's Answer #813475 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "Outside temperature over a day can be modelled as a sinusoidal function.
\n" ); document.write( "Suppose you know the high temperature for the day is 90 degrees and the low temperature of 80 degrees occurs at 6 AM.
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document.write( "The difference between the highest and lowest temperature is 90 - 80 = 10 degrees;  \r\n" );
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document.write( "hence, the midline is 85 degrees and the amplitude is  \"10%2F2\" = 5 degrees.\r\n" );
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document.write( "Next, if x is the time starting from 6 am (x= 0 when the temperature is lowest), then OBVIOUSLY, the temperature as a function of x is\r\n" );
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document.write( "    D(x) = \"85+-+5%2Acos%282pi%2A%28x%2F24%29%29\"      (1)\r\n" );
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document.write( "(we use the sign  \" - \"  to reflect cosinusoid about the midline, and we use the ratio x/24 to model the period of 24 hours).\r\n" );
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document.write( "Now, if t is the time after midnight, then x = t-6,  so the formula (1) takes the final form\r\n" );
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document.write( "    D(t) = \"85+-+5%2Acos%282pi%2A%28%28t-6%29%2F24%29%29\".        ANSWER\r\n" );
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document.write( "Or, if you like to use degrees instead of radians, then the same formula takes an EQUIVALENT form\r\n" );
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document.write( "    D(t) = \"85+-+5%2Acos%2815%5Eo%2A%28t-6%29%29\".          ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "How tutor  @Theo solved the problem,  is a formal presentation;  but as far as I know,  in reality, \r
\n" ); document.write( "\n" ); document.write( "nobody solves such problems in this way,  and  (in my opinion)  it is not a good way to teach students.\r
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\n" ); document.write( "\n" ); document.write( "I am 100% convinced that after such teaching,  although formally it is right,  the students' understanding will be  ZERO.\r
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\n" ); document.write( "\n" ); document.write( "What I showed you in my post,  is a way to solve such problems  using common sense \r
\n" ); document.write( "\n" ); document.write( "(combined with the knowledge of elementary  Trigonometry).  I hope, it is much more educative.\r
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