document.write( "Question 1183120: A statistics practitioner calculated the mean and the standard deviation from a sample of 51 observations. The sample mean= 120 and sample standard deviation= 15. To estimate the population mean with 90% confidence, the interval would have the lower and upper limits as: \n" ); document.write( "
Algebra.Com's Answer #813292 by Boreal(15235) You can put this solution on YOUR website! half-interval for a 90% CI t-dist would be t (0.95, df=50)*s/sqrt(n) \n" ); document.write( "=1.676*15/sqrt(51)=3.52 \n" ); document.write( "CI=(116.48, 123.52) \n" ); document.write( " \n" ); document.write( " |