The sum of two numbers exceeds a third number by four. If the sum of the three numbers is at least 20 and at most 28, find any three integral values satisfying the inequality.
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document.write( "Let 1st, 2nd, and 3rd, be F, S, and T, respectively
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document.write( "Then we get: F + S = T + 4 ------ eq (i)
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document.write( "Also, 
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-------- Substituting T + 4 for F + S
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document.write( " 8 ≤ T (3rd integer) ≤ 12
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document.write( "From the above, 5 scenarios exist. They are:
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document.write( "1) With T, or 3rd being 8, the sum of F (1st), and S (2nd) is 8 + 4, or 12. Use ANY 2 integers that sum to 12 to get the 1st and 2nd integers.
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document.write( "2) With T, or 3rd being 9, the sum of F (1st), and S (2nd) is 9 + 4, or 13. Use ANY 2 integers that sum to 13 to get the 1st and 2nd integers.
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document.write( "3) With T, or 3rd being 10, the sum of F (1st), and S (2nd) is 10 + 4, or 14. Use ANY 2 integers that sum to 14 to get the 1st and 2nd integers.
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document.write( "4) With T, or 3rd being 11, the sum of F (1st), and S (2nd) is 11 + 4, or 15. Use ANY 2 integers that sum to 15 to get the 1st and 2nd integers.
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document.write( "5) With T, or 3rd being 12, the sum of F (1st), and S (2nd) is 12 + 4, or 16. Use ANY 2 integers that sum to 16 to get the 1st and 2nd integers.
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