document.write( "Question 1183090: My father’s age 5 years ago plus twice my age now gives 65. My age 5 years ago plus three times my father’s age now gives 130. What is my father’s age.
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Algebra.Com's Answer #813267 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "My father’s age 5 years ago plus twice my age now gives 65. My age 5 years ago plus three times my father’s age now gives 130. What is my father’s age.
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Father is NOT 38 years-old, so: \"cross%28highlight%28f=38%29%29\"
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document.write( "Let father's age be F, and mine, M
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document.write( "We then get: F - 5 + 2M = 65______F + 2M = 70 ----- eq (i)
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document.write( "Also, M - 5 + 3F = 130_____M = 135 - 3F ----- eq (ii)
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document.write( "F + 2(135 - 3F) = 70 ------ Substituting 135 - 3F for M in eq (i)
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document.write( "F + 270 - 6F = 70
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document.write( "- 5F = - 200
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document.write( "Father or  \n" );
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