document.write( "Question 1183093: The sum of two numbers exceeds a third number by four. If the sum of the three numbers is at least 20 and at most 28, find any three integral values satisfying the inequality. \n" ); document.write( "
Algebra.Com's Answer #813254 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! numbers are x, y, z \n" ); document.write( "x+y=z+4 \n" ); document.write( "x+y+z=20; x+y+z=28 \n" ); document.write( "substitute \n" ); document.write( "2z+4=20 \n" ); document.write( "z=8 \n" ); document.write( "z+4=12 \n" ); document.write( "so 2 integers whose sum is 12 \n" ); document.write( "5 and 7, with z=8 \n" ); document.write( "4 and 8, with z=8 \n" ); document.write( "---- \n" ); document.write( "2z+4=28 \n" ); document.write( "z=12 \n" ); document.write( "x+y=16 \n" ); document.write( "0 and 16 works with z=12 \n" ); document.write( "1 and 15 works with z=12 \n" ); document.write( "- \n" ); document.write( "can set up for other integers between 20 and 28\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |