document.write( "Question 1183093: The sum of two numbers exceeds a third number by four. If the sum of the three numbers is at least 20 and at most 28, find any three integral values satisfying the inequality. \n" ); document.write( "
Algebra.Com's Answer #813254 by Boreal(15235)\"\" \"About 
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numbers are x, y, z
\n" ); document.write( "x+y=z+4
\n" ); document.write( "x+y+z=20; x+y+z=28
\n" ); document.write( "substitute
\n" ); document.write( "2z+4=20
\n" ); document.write( "z=8
\n" ); document.write( "z+4=12
\n" ); document.write( "so 2 integers whose sum is 12
\n" ); document.write( "5 and 7, with z=8
\n" ); document.write( "4 and 8, with z=8
\n" ); document.write( "----
\n" ); document.write( "2z+4=28
\n" ); document.write( "z=12
\n" ); document.write( "x+y=16
\n" ); document.write( "0 and 16 works with z=12
\n" ); document.write( "1 and 15 works with z=12
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\n" ); document.write( "can set up for other integers between 20 and 28\r
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