document.write( "Question 1183057: Given the sample mean = 22.625, sample standard deviation = 4.9339, and N = 40 for the low income group,
\n" ); document.write( "Test the claim that the mean nickel diameter drawn by children in the low income group is greater than 21.21 mm.
\n" ); document.write( "Teat at the 0.05 significance level.\r
\n" ); document.write( "\n" ); document.write( "a) Identify the correct alternative hypothesis: = > 21.21\r
\n" ); document.write( "\n" ); document.write( "Give all answers correct to 3 decimal places.\r
\n" ); document.write( "\n" ); document.write( "b) The test statistic value is:\r
\n" ); document.write( "\n" ); document.write( "c) Using the Traditional method, the critical value is:
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Algebra.Com's Answer #813243 by Theo(13342)\"\" \"About 
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the sample mean is 22.625 and the sample standard deviation is 4.9339.
\n" ); document.write( "the sample size is 40.
\n" ); document.write( "test mean is 21.21 and test is whether the sample mean is greater than that.\r
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\n" ); document.write( "\n" ); document.write( "test is whether sample mean is greater than test mean.\r
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\n" ); document.write( "\n" ); document.write( "standard error = sample standard deviation / sqrt(sample size) = 4.9339 / sqrt(40) = .780118 rounded to 6 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "t-score = (x - m) / s
\n" ); document.write( "x is the samplemean.
\n" ); document.write( "m is the test mean
\n" ); document.write( "s is the stnadard error\r
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\n" ); document.write( "\n" ); document.write( "t = (22.625 - 21.21) / .780118 = 1.814 rounded to 3 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "critical p-value is .05
\n" ); document.write( "test is one tailed, therefore critical p-value is .05 on the high end, because the test is whether the sample mean is greater than the test mean.\r
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\n" ); document.write( "\n" ); document.write( "h0 = 21.21
\n" ); document.write( "ha = 22.625\r
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\n" ); document.write( "\n" ); document.write( "degrees of freedom = 40 minus 1 = 39\r
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\n" ); document.write( "\n" ); document.write( "p-value for area to the right of t-value of 1.814 with 39 degrees of freedom is .0387 rounded to 4 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "since this is less than .05, results are significant and alternate hypothesis is accepted.\r
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\n" ); document.write( "\n" ); document.write( "here are the results from the t-test calculator at https://www.socscistatistics.com/pvalues/tdistribution.aspx\r
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\n" ); document.write( "\n" ); document.write( "test statistic is t-value of 1.814 rounded to 3 decimal places.
\n" ); document.write( "test p-value is .039 rounded to 3 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "any questions, send me a message.\r
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