document.write( "Question 1183075: Help me:
\n" ); document.write( "Find the Domain and solve:
\n" ); document.write( " $\"0.04%5E%283-sqrt%283x%2B2%29%29=25%2A5%5Esqrt%283x%2B2%29\"$
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Algebra.Com's Answer #813226 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "Find the Domain and solve $\"0.04%5E%283-sqrt%283x%2B2%29%29=25%2A5%5Esqrt%283x%2B2%29\"$
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document.write( "Your starting equation is\r\n" );
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document.write( "    .      (1)\r\n" );
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document.write( "The domain is the set of all x, such that  3x + 2 >= 0,  i.e.  x > .\r\n" );
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document.write( "To solve the equation, notice that  0.04 = ;  so, equation (1) takes the form\r\n" );
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document.write( "     = ,   or\r\n" );
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document.write( "    \r\n" );
document.write( "     = ,  which is the same as\r\n" );
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document.write( "     = .\r\n" );
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document.write( "The bases are the same in both sides of the equation;  hence, the indexes are the same\r\n" );
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document.write( "     = \r\n" );
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document.write( "which implies\r\n" );
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document.write( "    sqrt(3x+2) = 2 + 2*3 = 8\r\n" );
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document.write( "    3x+2 = 8^2 = 64\r\n" );
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document.write( "    3x = 64 - 2 = 62\r\n" );
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document.write( "     x = .      ANSWER\r\n" );
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