document.write( "Question 111508: Three consecutive integers are such that the square of the third is 76
\n" ); document.write( "more thant the square of the second. Find the integers.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #81318 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
THE THREE COSECUTIVE INTEGERS ARE X, X+1 & X+2.
\n" ); document.write( "(X+2)^2=(X+1)^2+76
\n" ); document.write( "X^2+4X+4=X^2+2X+1+76
\n" ); document.write( "4X-2X=-4+1+76
\n" ); document.write( "2X=73
\n" ); document.write( "X=73/2
\n" ); document.write( "X=36.5
\n" ); document.write( "X+1=37.5 ANSWER FOR THE SECOND NUMBER
\n" ); document.write( "X=2=38.5 ANSWER FOR THE THIRD NUMBER.
\n" ); document.write( "PROOF
\n" ); document.write( "(38.5^2=37.5^2+76
\n" ); document.write( "1482.25=1406.25+76
\n" ); document.write( "1482.25=1482.25
\n" ); document.write( "
\n" );