document.write( "Question 111508: Three consecutive integers are such that the square of the third is 76
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document.write( "more thant the square of the second. Find the integers.
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Algebra.Com's Answer #81318 by checkley71(8403) ![]() You can put this solution on YOUR website! THE THREE COSECUTIVE INTEGERS ARE X, X+1 & X+2. \n" ); document.write( "(X+2)^2=(X+1)^2+76 \n" ); document.write( "X^2+4X+4=X^2+2X+1+76 \n" ); document.write( "4X-2X=-4+1+76 \n" ); document.write( "2X=73 \n" ); document.write( "X=73/2 \n" ); document.write( "X=36.5 \n" ); document.write( "X+1=37.5 ANSWER FOR THE SECOND NUMBER \n" ); document.write( "X=2=38.5 ANSWER FOR THE THIRD NUMBER. \n" ); document.write( "PROOF \n" ); document.write( "(38.5^2=37.5^2+76 \n" ); document.write( "1482.25=1406.25+76 \n" ); document.write( "1482.25=1482.25 \n" ); document.write( " |