document.write( "Question 1183029: Find the area of a parallelogram bounded by the y-axis, the line
\n" ); document.write( "x = 4,
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\n" ); document.write( "f(x) = 4 + 2x,
\n" ); document.write( " and the line parallel to f(x) passing through
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Algebra.Com's Answer #813176 by ikleyn(52787) $\"\"$ $\"About$

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\n" ); document.write( "Find the area of a parallelogram bounded by the y-axis, the line
\n" ); document.write( "x = 4,
\n" ); document.write( "the line
\n" ); document.write( "f(x) = 4 + 2x,
\n" ); document.write( "and the line parallel to f(x) passing through
\n" ); document.write( "(2, 6).
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document.write( "The line  f(x) = 4 + 2x  has  y-intercept of  f(0) = 4 + 2*0 = 4.\r\n" );
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document.write( "The line parallel to  f(x) = 4 + 2x  and passing through  (2,6)  is  y = Const + 2x\r\n" );
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document.write( "with Const = 6 - 2*2 = 2; so, the parallel line is  y = 2 + 2x,  and it has y-intercept of  y = 2.\r\n" );
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document.write( "Thus, our parallelogram has the base length of  4-2 = 2 units (along the y-axis) and the height of 4 units\r\n" );
document.write( "(the distance from y-axis to vertical line x= 4).\r\n" );
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document.write( "THEREFORE, the area of our parallelogram is the product of the base and height measures, i.e. 2*4 = 8 square units.    ANSWER\r\n" );
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