document.write( "Question 1183010: On average, it needs 250,000 dollars per year and an additional 600,000 dollars every 4 years for major repairs to maintain a certain three-storey office building. How much must be paid now to take care of these payments on a bank that offers 8% per year?\r
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\n" ); document.write( "\n" ); document.write( "|I get confused on the interest rate, what will I use if solving for the \"every four years\"? Please help me..
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Algebra.Com's Answer #813156 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
every year you divide 250,000 by 1.08 raised to the power of the (year minus the start year).\r
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\n" ); document.write( "\n" ); document.write( "every 4 years, you divide 600,000 by 1.08 raised to the power of the (year minus the start year).\r
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\n" ); document.write( "\n" ); document.write( "example:\r
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\n" ); document.write( "\n" ); document.write( "in year 1, 250,000 is divided by 1.08^1.
\n" ); document.write( "in year 2, 250,000 is divided by 1.08^2.
\n" ); document.write( "in year 3, 250,000 is divided by 1.08^3.
\n" ); document.write( "in year 4, 250,000 is divided by 1.08^4\r
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\n" ); document.write( "\n" ); document.write( "in addition, .....\r
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\n" ); document.write( "\n" ); document.write( "in year 4, 600,000 is divided by 1.08^4.\r
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\n" ); document.write( "\n" ); document.write( "note that:\r
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\n" ); document.write( "\n" ); document.write( "1.08 - 1 = .08
\n" ); document.write( ".08 * 100 = 8%.\r
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\n" ); document.write( "\n" ); document.write( "1.08^4 = 1.36048896
\n" ); document.write( "1.36048896 - 1 = .36048896
\n" ); document.write( ".36048896 * 100 = 36.048896%\r
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\n" ); document.write( "\n" ); document.write( "you do that for the number of years indicated.
\n" ); document.write( "they should be in increments of 4, since there is that additional charge every 4 years.\r
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\n" ); document.write( "\n" ); document.write( "over 20 years, your present value will be equal to $3,761,847.55.\r
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\n" ); document.write( "\n" ); document.write( "the following spreadsheet shows the calculations.\r
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