document.write( "Question 1182925: Suppose the age a female has her first period is normally distributed with a mean age of
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document.write( "12 years and standard deviation of 2.5 years.
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document.write( "a. Calculate the probability of randomly selecting a female who will have her first
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document.write( "period after 14 years.
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document.write( "b. Calculate the probability of randomly selecting a female who will have her first
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document.write( "period before 10 years old.
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document.write( "c. Calculate the percentage of females who will have their first period between 12 years
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document.write( "old and 17 years old.
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document.write( "d. A man has a daughter who is now 21 years old and still did not have her first period.
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document.write( "Should he be worried? Explain based on your knowledge of variables that follows a
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document.write( "normal distribution. \n" );
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Algebra.Com's Answer #813143 by Boreal(15235) You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( ">(14-12)/2.5 is z>0.8 with probability 0.2119 \n" ); document.write( "- \n" ); document.write( "< (10-12)/2.5 is z < -0.8 with same probability of 0.2119 \n" ); document.write( "- \n" ); document.write( "between 12 and 17, this will be with z between 0 and 2 with probability 0.4772 \n" ); document.write( "also 2ndVARS 2 normalcdf(12,17,12,2.5) ENTER \n" ); document.write( "- \n" ); document.write( "greater than 21 will be a z>9/2.5 or 3.6 with probability 0.00016. This is very low probability from a statistical standpoint and by age 15 without one a girl has the diagnosis of primary amenorrhea and should be evaluated for hormonal and other issues. \n" ); document.write( " |