document.write( "Question 1182979: A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 430 babies were born, 344 of them were girls. Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born. Based on result, does the method appear to be effective?\r
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document.write( "The proportion is different from 0.5? \n" );
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Algebra.Com's Answer #813142 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! p hat=344/430=0.8 \n" ); document.write( "half-interval is z(0.995)*sqrt(.8*.2/430) \n" ); document.write( "=2.575*sqrt(.16/430) \n" ); document.write( "=0.0497 \n" ); document.write( "the interval is 0.75 < p < 0.85 \n" ); document.write( "Since the interval does not contain 0.5, yes, the proportion is different from 0.5 \n" ); document.write( " \n" ); document.write( " |