document.write( "Question 1182992: Find the equation of the straight line which
\n" ); document.write( "passes through the point(-3,5) and is
\n" ); document.write( "perpendicular to the line 2x-4y+3=0?
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Algebra.Com's Answer #813123 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Using basic algebra....

\n" ); document.write( "(1) Find the slope of the given line

\n" ); document.write( "2x-4y+3=0
\n" ); document.write( "4y = 2x+3
\n" ); document.write( "y = (1/2)x+3/4

\n" ); document.write( "The slope is 1/2; the slope of a line perpendicular to that line is -2/1, or just -2.

\n" ); document.write( "(2) Use the general slope-intercept form of the equation with the desired slope of -2 passing through (x,y) = (-3,5) to find the equation

\n" ); document.write( "y = mx+b
\n" ); document.write( "5 = (-2)(-3)+b
\n" ); document.write( "5 = 6+b
\n" ); document.write( "b = -1

\n" ); document.write( "ANSWER: y = -2x-1

\n" ); document.write( "A faster path to the answer....

\n" ); document.write( "Given the equation 2x-4y+3=0, any line parallel to that line has the form 2x-4y+C=0 for some constant C, and any line perpendicular to that line has the form 4x+2y+C=0 for some constant C (switch the coefficients of x and y and change the sign of one of them).

\n" ); document.write( "So we are looking for an equation of the form 4x+2y+C=0 that is satisfied by (x,y) = (-3,5):

\n" ); document.write( "4(-3)+2(5)+C=0
\n" ); document.write( "-12+10+C=0
\n" ); document.write( "C=2

\n" ); document.write( "The equation we want is

\n" ); document.write( "4x+2y+2=0

\n" ); document.write( "That is equivalent to the answer we got using basic algebra:

\n" ); document.write( "4x+2y+2=0
\n" ); document.write( "2y = -4x-2
\n" ); document.write( "y = -2x-1

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