document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182989>Question 1182989</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of right triangle is 15mc. One of the legs is 3cm more than the other. Find the length of the two legs.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #813118 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=813118\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two legs be x and x+3.<BR>\n" );
document.write( "The hypotenuse of right triangle is 15cm.<BR>\n" );
document.write( "For a right angled triangle the square of the hypotenuse is equal to the sum of squares of the other two sides.<BR>\n" );
document.write( "Plugging in the values we get, x^2+(x+3)^2=15^2<BR>\n" );
document.write( "Simplifying we get,<BR>\n" );
document.write( "2x^2+6x+9=225<BR>\n" );
document.write( "2x^2+6x+9-225=0<BR>\n" );
document.write( "2x^2+6x-216=0<BR>\n" );
document.write( "x^2+3x-108=0<BR>\n" );
document.write( "x^2+12x-9x-108=0<BR>\n" );
document.write( "x(x+12)-9(x+12)=0<BR>\n" );
document.write( "(x-9)(x+12)=0<BR>\n" );
document.write( "x-9=0 or x+12=0<BR>\n" );
document.write( "x=9 or x=-12<BR>\n" );
document.write( "x=9 is the correct answer as x cannot be negative.<BR>\n" );
document.write( "The two legs of the triangle are 9 and 12 respectively. </SPAN>\n" );
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