document.write( "Question 1182984: Find the solutions of the equation cos 2x + cos 𝑥 + 1 = 0 in the interval [0, 2𝜋). Check your answer if it is a solution or not. \n" ); document.write( "
Algebra.Com's Answer #813117 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
cos2x + cosx + 1 = cos^2x - sin^2x + cosx + cos^2 x + sin^2x = 2cos^2x + cosx = 0\r
\n" ); document.write( "\n" ); document.write( "==> cosx(2cosx + 1) = 0 ==> cos x = 0 or 2cosx + 1 = 0\r
\n" ); document.write( "\n" ); document.write( "cosx = 0 ==> x = \"pi%2F2\" or \"3%2Api%2F2\" \r
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\n" ); document.write( "\n" ); document.write( "2cosx + 1 = 0 ==> x = \"2%2Api%2F3\" or \"4%2Api%2F3\"
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