document.write( "Question 1182970: Compute:
\n" ); document.write( "(1+√-2)/2-(1-√(-1/2))
\n" ); document.write( "There is a little note on the problem too:
\n" ); document.write( "\"Since $\"i%5E2\"$ =−1, then −1=±i. However, for this problem use the principal root of (−1), namely −1=i. For square root of a positive real number use principal root (the positive root) as well.\" \n" ); document.write( "

Algebra.Com's Answer #813106 by MathLover1(20849) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " $\"%281%2Bsqrt%28-2%29%29%2F2-%281-sqrt%28-1%29%2Fsqrt%282%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"1%2F2%2Bsqrt%28-2%29%2F2-1%2Bsqrt%28-1%29%2Fsqrt%282%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"-1%2F2%2Bi%2Asqrt%282%29%2F2%2Bi%2Asqrt%281%29%2Fsqrt%282%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"-1%2F2%2Bi%2Asqrt%282%29%2F2%2Bi%2A1%2Fsqrt%282%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"-1%2F2%2Bi%2Asqrt%282%29\"$ \r
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