document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182969>Question 1182969</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to solve the following proportion problem:\r<BR>\n" );
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document.write( "\"If p varies proportionally to s, and p = 6 when s = 3, which of the following equations correctly models this relationship?\"\r<BR>\n" );
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document.write( "1. p = 2s\r<BR>\n" );
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document.write( "2. p = s/3<BR>\n" );
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document.write( "3. p = s + 3\r<BR>\n" );
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document.write( "4. s = 2p\r<BR>\n" );
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document.write( "I am trying to understand the phrase \"if p varies proportionally to s.\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #813099 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=813099\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p=ks where k is the constant of proportionality. P is directly proportional to s. This problem.<BR>\n" );
document.write( "p=k/s, P is inversely proportional to s, so if s rises P falls.\r<BR>\n" );
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document.write( "What models this relationship is p=2s<BR>\n" );
document.write( "numbers 2 and 4 don't work, and while p is equal to s+3, that is not proportional, for 2s should equal 12 in the problem above, but 2s+3 would be 9. </SPAN>\n" );
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