document.write( "Question 1182743: A study of 420,065 cell phone users found that 136 of them developed cancer of the brain or nervous system. Prior to this study of cell phone​ use, the rate of such cancer was found to be 0.0316​% for those not using cell phones.\r
\n" ); document.write( "\n" ); document.write( "Use the sample data to construct a 95​% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system.\r
\n" ); document.write( "\n" ); document.write( "__% < p < __​%
\n" ); document.write( "(Round to three decimal places as​ needed.)
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Algebra.Com's Answer #813033 by Boreal(15235)\"\" \"About 
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The 95% half-interval is z(0.975)*sqrt(p*(1-p)/n)
\n" ); document.write( "=1.96*sqrt(0.000316*0.999684/420065)
\n" ); document.write( "=0.0000274; add that and subtract it from 0.000323, p hat.
\n" ); document.write( "so the interval is (0.000296, 0.000350)
\n" ); document.write( "or (0.030%, 0.0350%)\r
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