document.write( "Question 1182900: A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor. If each can has a weight of 5.50 N, what is the power being put out by the electric motor that drives the conveyor \n" ); document.write( "
Algebra.Com's Answer #813010 by ikleyn(52932) You can put this solution on YOUR website! . \n" ); document.write( "A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor. \n" ); document.write( "If each can has a weight of 5.50 N, what is the power being put out by the electric motor that drives the conveyor ? \n" ); document.write( "~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "The power P = 40 cans * 3.40 meters up * 5.50 N = 40*3.4*5.5 = 748 joules per second = 748 watts = 0.748 kilowatts. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved, answered and explained.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |