document.write( "Question 1182900: A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor. If each can has a weight of 5.50 N, what is the power being put out by the electric motor that drives the conveyor \n" ); document.write( "
Algebra.Com's Answer #813010 by ikleyn(52932)\"\" \"About 
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\n" ); document.write( "A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor.
\n" ); document.write( "If each can has a weight of 5.50 N, what is the power being put out by the electric motor that drives the conveyor ?
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document.write( "The power  P = 40 cans * 3.40 meters up * 5.50 N = 40*3.4*5.5 = 748 joules per second = 748 watts = 0.748 kilowatts.    ANSWER\r\n" );
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