document.write( "Question 2061: What is the 6th term of the geometric sequence in which a1=5 and r=3? Please help and explain the step(s) on how to do it. Also, how do you find the nth term a1=3, d=2 and n=7? thank you \n" ); document.write( "
Algebra.Com's Answer #813 by khwang(438)\"\" \"About 
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For a geometric sequence with given a1 and r, we have\r
\n" ); document.write( "\n" ); document.write( " a(n) = a(1)* r^(n-1),\r
\n" ); document.write( "\n" ); document.write( " So,when n = 6, a(6) = a(1)* r^5 = 5*37^5 = 346719785.\r
\n" ); document.write( "\n" ); document.write( " For arithemic series with given a1 and d, we have\r
\n" ); document.write( "\n" ); document.write( " a(n) = a(1) + (n-1) d
\n" ); document.write( " When n = 7, a(1) = 3,d =2, a(7) = 3 + 6 * 2 = 15.\r
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\n" ); document.write( "\n" ); document.write( " It seems you have to remember these basic formulas.\r
\n" ); document.write( "\n" ); document.write( " Kenny\r
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