document.write( "Question 1182842: Two masses 6.0 kg and 9.0 kg are hung from the two ends of a cord which passes over a smooth pulley so that the two masses hang freely. If initially the 9.0 kg mass is 4 meters from the floor, how long will it take this mass to reach the floor after the masses are released?
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Algebra.Com's Answer #812944 by ikleyn(52776)\"\" \"About 
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\n" ); document.write( "Two masses 6.0 kg and 9.0 kg are hung from the two ends of a cord which passes over a smooth pulley
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document.write( "The acting force in the system is the \"net force\", which is equal to the difference of the masses' weights\r\n" );
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document.write( "    9*g - 6*g = 9*10 - 6*10 = 90 - 60 newtons = 30 newtons.\r\n" );
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document.write( "The total mass of the moving system is the SUM of the masses  6 kg + 9 kg = 15 kg.\r\n" );
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document.write( "THEREFORE, the acceleration of the masses is  a = \"30_newtons%2F15_kilograms\" = 2 m/s^2,\r\n" );
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document.write( "according to the Newton's second law.\r\n" );
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document.write( "The time to reach the floor is  determined by the equation  for the uniformly accelerated body  \"%28at%5E2%29%2F2\" = 4 meters;\r\n" );
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document.write( "from this equation,  t = \"sqrt%28%284%2A2%29%2Fa%29\" = \"sqrt%28%284%2A2%29%2F2%29\" = \"sqrt%284%29\" = 2 seconds.    ANSWER\r\n" );
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