document.write( "Question 1182844: A 50 N block is placed on a smooth inclined plane which is 5 meters long and 3 meters high. (a) What force parallel to the plane and applied to the block will keep the block in equilibrium? (b) What force is applied by the plane to the block? \n" ); document.write( "

Algebra.Com's Answer #812943 by ikleyn(52835) $\"\"$ $\"About$

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document.write( "(a)  This force is  50*sin(a) =  = 30 newtons.    ANSWER\r\n" );
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document.write( "     This force is OPPOSITE to the ROLLING force and is directed parallel to the inclined plane.\r\n" );
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document.write( "(b)  This force is  50*cos(a) =  = 40 newtons.   ANSWER\r\n" );
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document.write( "     This force is called \"the REACTION force\". It is PERPENDICULAR to the inclined plane.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.     //     All question are answered.\r
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\n" ); document.write( "\n" ); document.write( "In my solution,   \" a \"   is the angle of the inclined plane to horizontal.\r
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\n" ); document.write( "\n" ); document.write( "        sin(a) = $\"3%2F5\"$ .         cos(a) = $\"sqrt%281-sin%5E2%28a%29%29\"$ = $\"sqrt%281-%283%2F5%29%5E2%29\"$ = $\"4%2F5\"$ .\r
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