document.write( "Question 1182828: At the instant a truck is travelling along a level pavement at 20 m/s, a wooden crate falls from the truck. If the crate travels 40 meters before coming to rest, what is the coefficient of kinetic friction between the crate and the road? \n" ); document.write( "
Algebra.Com's Answer #812918 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "At the instant a truck is travelling along a level pavement at 20 m/s, a wooden crate falls from the truck.
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document.write( "In this Physics problem, we are given that a wooden crate slides along the level pavement,\r\n" );
document.write( "having the initial speed of 20 m/s, and stops after traveling 40 meters.\r\n" );
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document.write( "The simplest way to solve the problem is to apply the Law of Conservation mechanical energy.\r\n" );
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document.write( "From one side, we have the kinetic energy  \"%28mv%5E2%29%2F2\"  of the sliding crate,\r\n" );
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document.write( "where  \"m\"  is its mass and \"v\"  is its initial speed.\r\n" );
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document.write( "From the other side, we have the work of the friction force  F*d,  where F is the friction force  k*(m*g),\r\n" );
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document.write( "k is the kinematic friction coefficient,  g is the gravity acceleration and  \"d\"  is the the breaking distance (given).\r\n" );
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document.write( "The Conservation Law of mechanical energy allows us to write this equation\r\n" );
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document.write( "    \"%28m%2Av%5E2%29%2F2\" = k*m*g*d.\r\n" );
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document.write( "First, we cancel the mass in both sides and then we get the formula for the friction coefficient\r\n" );
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document.write( "    k = \"%28v%5E2%29%2F%282%2Ag%2Ad%29\" = \"20%5E2%2F%282%2A10%2A40%29\" = \"1%2F2\" = 0.5.\r\n" );
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document.write( "ANSWER.  Under given conditions, the kinematic friction coefficient is  0.5.\r\n" );
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