document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182811>Question 1182811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A survey of 66 randomly selected homeowners finds that they spend a mean of $70 per month on home maintenance. Construct a 99% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners. Assume that the population standard deviation is $12 per month. Round to the nearest cent. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812899 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the half-interval is z(0.995, df=65)*sigma/sqrt(n)<BR>\n" );
document.write( "2.57583*12/sqrt(66)=$3.804 or $3.80<BR>\n" );
document.write( "($66.20, $73.80)<BR>\n" );
document.write( "Note: if z is rounded, the result may change by a cent.\r<BR>\n" );
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