document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182808>Question 1182808</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that a sample is used to estimate a population proportion p.<BR>\n" );
document.write( "Find the 99% confidence interval for a sample of size 351 with 65% successes.<BR>\n" );
document.write( "Answer as a tri-linear inequality using decimals (not percents) accurate to 3 decimal places.\r<BR>\n" );
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document.write( "_______ < p < _________ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812895 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1-sample proportion 99%CI z-int<BR>\n" );
document.write( "half interval is z(0.995)+/- sqrt (p(1-p)/n)<BR>\n" );
document.write( "=2.576*sqrt (0.65*0.35/351)<BR>\n" );
document.write( "=0.0656 or 0.066<BR>\n" );
document.write( "add to and subtract from mean<BR>\n" );
document.write( "0.584 < p < 0.716.  The result may change slightly on how much z is rounded in the intermediate calculations. I took it to four decimal places. </SPAN>\n" );
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