document.write( "Question 1182798: The 4-digit number pqrs has the property that pqrs*4=srqp. If p=2, what is the value of the 3-digit number qrs? \n" ); document.write( "
Algebra.Com's Answer #812888 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "In the link from the other tutor, several slightly different algebraic solutions to the problem are shown. \n" ); document.write( "I think the problem is easily solved without algebra, using what we know from early in our mathematics education about multiplication. \n" ); document.write( "We have... \r\n" ); document.write( " pqrs\r\n" ); document.write( " * 4\r\n" ); document.write( " ----\r\n" ); document.write( " srqp \n" ); document.write( "and we are told that p is 2. \n" ); document.write( "Note that knowing that p=2 only makes the problem easier to solve; there is in fact only one solution to the problem, and in that solution p is 2. So let's look at the problem without using the given information that p is 2. We will quickly determine that by logical analysis. \n" ); document.write( "(1) In the units column of the multiplication, we have s times 4 giving final digit p; that means p is even. \n" ); document.write( "(2) For the leading digits, we have p times 4 giving us s; and the product is a 4-digit number. \n" ); document.write( "So (1) and (2) tell us p is even, and 4 times p is less than 10. p can't be 0, so p can only be either 1 or 2. p \"even\" and \"either 1 or 2\" means p is 2. \n" ); document.write( "So now we have... \r\n" ); document.write( " 2qrs\r\n" ); document.write( " * 4\r\n" ); document.write( " ----\r\n" ); document.write( " srq2 \n" ); document.write( "(3) Now in the units column we have s times 4 giving final digit 2, so s is either 3 or 8. \n" ); document.write( "(4) And for the leading digits we have 2 times 4 giving final digit s, so s is either 8 or 9. \n" ); document.write( "So (3) and (4) tell us that s must be 8. \n" ); document.write( "So now we have... \r\n" ); document.write( " 2qr8\r\n" ); document.write( " * 4\r\n" ); document.write( " ----\r\n" ); document.write( " 8rq2 \n" ); document.write( "(5) For the last two digits, we now have 4 times \"r8\" giving final digit 2. 4 times r is even, and the 4 times 8 gives us a \"carry\" of 3; that means q is odd. \n" ); document.write( "(6) For the first two digits, we have \"2q\" times 4 giving us \"8r\"; that means q is at most 2. \n" ); document.write( "So q is an odd digit that is at most 2; of course that means q is 1. \n" ); document.write( "So now we have... \r\n" ); document.write( " 21r8\r\n" ); document.write( " * 4\r\n" ); document.write( " ----\r\n" ); document.write( " 8r12 \n" ); document.write( "(7) Again for the final two digits we have \"r8\" times 4 giving us tens digit 1. With the \"carry\" of 3 from the units column, that means r times 4 gives us final digit 8, so r is either 2 or 7. \n" ); document.write( "(8) And for the leading two digits, \"21\" times 4 gives us leading digits \"8r\", so r can be 4, 5, 6, or 7. \n" ); document.write( "And that tells us r must be 7. \n" ); document.write( "So now we have the unique final answer for pqrs times 4 being equal to srqp: \r\n" ); document.write( " 2178\r\n" ); document.write( " * 4\r\n" ); document.write( " ----\r\n" ); document.write( " 8712 \n" ); document.write( "Solved... without algebra. \n" ); document.write( " \n" ); document.write( " |