document.write( "Question 1182752: A small boat sends a distress signal giving its location as 10 miles from shore in choppy seas and says it is making only 5 knots. A Coast Guard boat is dispatched from shore to give aid: it averages 20 knots. How long before it meets the disabled boat if they are traveling toward each other? How far did each travel?\r
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Algebra.Com's Answer #812824 by greenestamps(13214) You can put this solution on YOUR website! \n" ); document.write( "The ratio of the speeds of the two boats is 20:5 = 4:1, so the ratio of distances traveled is 4:1. \n" ); document.write( "If your mental arithmetic is good, you can solve that mentally -- the small boat travels 2 of the 10 miles and the Coast Guard boat travels 8. \n" ); document.write( "Or if you need to use formal algebra, using the ratio 4:1 of the distances traveled by the two boats, the small boat travels x miles and the Coast Guard boat travels 4x miles, and the total distance traveled is 10 miles: \n" ); document.write( "x+4x=10 \n" ); document.write( "5x=10 \n" ); document.write( "x=2 \n" ); document.write( "4x=8 \n" ); document.write( "The required time can be determined using the distance and speed of either boat: 2 miles at 5 knots for the small boat or 8 miles at 20 knots for the Coast Guard boat. \n" ); document.write( "Of course you need to deal with the conversion between knots and miles per hour; that part I leave to you. \n" ); document.write( " \n" ); document.write( " |