document.write( "Question 1182718: The net force on a 2-kg body is 6 N. If the body is originally travelling with a velocity of 8 m/s, and if the force applied is opposite to the velocity, find the distance it will move before coming to rest. \n" ); document.write( "
Algebra.Com's Answer #812800 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "The net force on a 2-kg body is 6 N. If the body is originally travelling with a velocity of 8 m/s,
\n" ); document.write( "and if the force applied is opposite to the velocity, find the distance it will move before coming to rest.
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document.write( "(1)  First we find the deceleration  \"a\"  by dividing the force by the mass (the second Newton's law)\r\n" );
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document.write( "         a = \"F%2Fm\" = \"6_N%2F2_kg\" = 3 m/s^2.\r\n" );
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document.write( "(2)  Next we find the time to get the zero speed from the basic kinematic equation\r\n" );
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document.write( "         v = a*t,\r\n" );
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document.write( "where v is the initial velocity of 8 m/s (given) and \"a\" is the deceleration  a = 3 m/s^2, found above in step (1)\r\n" );
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document.write( "         t = \"v%2Fa\" = \"8%2F3\" = 2.66666... seconds.\r\n" );
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document.write( "(3)   Finally, we find the distance\r\n" );
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document.write( "          d = \"%28a%2At%5E2%29%2F2\" = \"%283%2A%288%2F3%29%5E2%29%2F2\" = \"64%2F%282%2A3%29\" = \"32%2F3\" = 10 \"2%2F3\"  meters.      ANSWER\r\n" );
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