document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182687>Question 1182687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A data set includes 108 body temperatures of healthy adult humans having a mean of 98.3°F and a standard deviation of 0.69°F. Construct a 99​% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body​ temperature?\r<BR>\n" );
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document.write( "What is the confidence interval estimate of the population mean μ​? <BR>\n" );
document.write( "__°F < μ < __°F<BR>\n" );
document.write( "(Round to three decimal places as​ needed.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812781 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the half-interval is a t(0.995, df=107)*s/sqrt(n)=2.623*0.69/sqrt(107)=0.175<BR>\n" );
document.write( "the interval is (98.125, 98.475)<BR>\n" );
document.write( "This would suggest that 98.6 is too high to use as the mean body temperature, since it lies outside the confidence interval. </SPAN>\n" );
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