document.write( "Question 1182631: Using synthetic division, find one zero of the polynomial f(x)=x^3+c^2-57x+135 then write the polynomial in factored form based on the zero you found:
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document.write( "Zero for the polynomial: f(__) = 0
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document.write( "Factors of the polynomial based on the above zero: f(x)= \n" );
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Algebra.Com's Answer #812728 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Using synthetic division, find one zero of the polynomial f(x)=x^3+c^2-57x+135 \n" ); document.write( " I think this is: f(x) = x^3 + x^2 - 57x + 135 \n" ); document.write( "Try the lowest factor of 135, 3 \n" ); document.write( ": \n" ); document.write( ".....___________________ \n" ); document.write( " 3 | 1 + 1 - 57 + 135 \n" ); document.write( "............3 + 12 - 135 \n" ); document.write( "....-------------------- \n" ); document.write( "......1 + 4 - 45 + 0 \n" ); document.write( ": \n" ); document.write( "then write the polynomial in factored form based on the zero you found: \n" ); document.write( "(x-3)(x^2 + 4x - 45) \n" ); document.write( "Zero for the polynomial: f(__) = 0 \n" ); document.write( "Factor (x^2+4x-45): (x+9)(x-5) \n" ); document.write( "Factors of the polynomial based on the above zero: \n" ); document.write( "f(x)= (x-3)(x-5)(x+9) \n" ); document.write( " |