document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182613>Question 1182613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A student in a chemistry laboratory wants to form a<BR>\n" );
document.write( "32 ml mixture of 2 solutions to contain 30% acid.<BR>\n" );
document.write( "Solution A contains 42% acid and solution B<BR>\n" );
document.write( "contains18% acid. How many ml of each solution<BR>\n" );
document.write( "must be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812696 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use  42% acid and 18% acid solutions to make 32 mL. of 30%.\r<BR>\n" );
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document.write( "If v mL. of 42%, then to account for pure acid,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=42v%2B18%2832-v%29=30%2A32 ALIGN=MIDDLE  ALT=\"42v%2B18%2832-v%29=30%2A32\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and solve for v.\r<BR>\n" );
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document.write( "Be aware that  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2842%2B18%29%2F2=30 ALIGN=MIDDLE  ALT=\"%2842%2B18%29%2F2=30\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so the student will need 16 mL. of each of the starting solutions of acid. </SPAN>\n" );
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