document.write( "Question 1182599: The following equation models the rate at which a worker produces so many units after x hours when the worker starts at 8AM. (Assume 8AM means x=0)
\n" ); document.write( "f(x)=-2x^2+8x+50\r
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\n" ); document.write( "\n" ); document.write( "At what time is the worker working most efficiently and how many units is the worker producing at this time?
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Algebra.Com's Answer #812674 by MathLover1(20850)\"\" \"About 
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The following equation models the rate at which a worker produces so many units after x hours when the worker starts at 8AM (Assume 8AM means x=0)\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-2x%5E2%2B8x%2B50\"\r
\n" ); document.write( "\n" ); document.write( "At what time is the worker working most efficiently and how many units is the worker producing at this time?\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-2x%5E2%2B8x%2B50\"-> this is downward parabola and max is at vertex\r
\n" ); document.write( "\n" ); document.write( "so, write equation in vertex form\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28-2x%5E2%2B8x%29%2B50\"...........factor out \"-2\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-2%28x%5E2-4x%29%2B50\".......complete square\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-2%28x%5E2-4x%2Bb%5E2%29-%28-2%29b%5E2%2B50\".......\"b=4%2F2=2\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-2%28x%5E2-4x%2B2%5E2%29%2B2%2A2%5E2%2B50\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-2%28x-2%29%5E2%2B8%2B50\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-2%28x-2%29%5E2%2B58\"\r
\n" ); document.write( "\n" ); document.write( "=>\"h=2\", \"k=58\"=> vertex is at (\"2\",\"58\")\r
\n" ); document.write( "\n" ); document.write( "Assuming \"8AM\" means \"x=0\", \"x=2\" will be \"10AM\"\r
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\n" ); document.write( "\n" ); document.write( "the worker working most efficiently at \"10AM\" and producing \"58\" units at this time \r
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