document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182592>Question 1182592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the potential energy of 3.00 kg object at the bottom of a well 10.0 m deep as measured from ground level. Explain the sign of the answer <BR>\n" );
document.write( "(b)  How much work is required to lift a 3.00 kg object from the bottom of a well 10.00 m deep </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812667 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "P E = m *g * h\r<BR>\n" );
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document.write( "height on ground is 0 m\r<BR>\n" );
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document.write( "height is negative below the ground\r<BR>\n" );
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document.write( "P E = 3 * 10m/s^2 * (-10)\r<BR>\n" );
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document.write( "PE =-300 Joules\r<BR>\n" );
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document.write( "Change in P E = work done<BR>\n" );
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