document.write( "Question 1182529: An Arctic tractor drags a 45 ton (that's metric ton 1 ton equals 1000 kg) across the snow which has a friction coefficient of 0.075 a distance of 4500 kilometers how much work did the tractor do \n" ); document.write( "

Algebra.Com's Answer #812608 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Convert all given data in kilograms and meters\r\n" );
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document.write( "    45 tons = 45000 kilograms (kg);\r\n" );
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document.write( "    4500 kilometers = 4500000 meters (m).\r\n" );
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document.write( "The friction force is the product of the weight by the friction coefficient k.\r\n" );
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document.write( "The weight is  W = 45000 kilograms * 10 m/s^2 = 450000 newtons.\r\n" );
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document.write( "The friction force is  F = k*W = 0.075*450000 = 33750 newtons.\r\n" );
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document.write( "The work done is the product of the friction force by the distance\r\n" );
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document.write( "    A = F*d = 33750 * 4500000 = 1.51875E+11 joules = 1.51875E+8  kilo-joules.   ANSWER\r\n" );
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