Algebra.Com's Answer #81254 by jim_thompson5910(35256)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "![](\"/cgi-bin/rendertex.cgi?\LARGE) Start with the given equation\r
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document.write( " Divide both sides by 9\r
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document.write( " Take the square root of both sides\r
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document.write( " Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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document.write( " Add 8 to both sides to isolate x.\r
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document.write( " Break down the expression into two parts:\r
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document.write( " or \r\n" );
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document.write( " Now combine like terms for each expression:\r
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document.write( " or \r
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document.write( "Answer:\r
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document.write( "So our solution is\r
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document.write( " or \r\n" );
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document.write( " Notice when we graph the equations  and  we get:\r
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document.write( " graph of (red) and (green)\r
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document.write( "Here we can see that the two equations intersect at x values of  and  , so this verifies our answer.\r
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document.write( "#2\r
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document.write( " | Solved by pluggable solver: Quadratic Formula | \n" );
document.write( "Let's use the quadratic formula to solve for x:
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document.write( " Starting with the general quadratic
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document.write( " the general solution using the quadratic equation is:
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document.write( " So lets solve  (note: since the polynomial does not have an \"x\" term, the 2nd coefficient is zero. In other words, b=0. So that means the polynomial really looks like  notice  ,  , and  )
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document.write( "  Plug in a=27, b=0, and c=-49
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document.write( "  Square 0 to get 0
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document.write( "  Multiply  to get 
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document.write( "  Combine like terms in the radicand (everything under the square root)
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document.write( "  Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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document.write( "  Multiply 2 and 27 to get 54
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document.write( " So now the expression breaks down into two parts
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document.write( "  or 
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document.write( " Now break up the fraction
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document.write( "  or 
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document.write( " Simplify
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document.write( "  or 
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document.write( " So the solutions are:
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document.write( " or
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document.write( " | \n" );
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document.write( "#3\r
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document.write( "  Start with the given equation\r
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document.write( "  Add  to both sides\r
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document.write( " Factor the left side (note: if you need help with factoring, check out this solver)\r
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document.write( "Now set each factor equal to zero:\r
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document.write( " or  \r
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document.write( " or  Now solve for x in each case\r
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document.write( "So our solutions are or \r
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document.write( "Notice if we graph  we get\r
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document.write( " \r
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document.write( "and we can see that the graph has roots at or , so this verifies our answer.\r
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document.write( "#4\r
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document.write( " Start with the given expression\r
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document.write( " Factor out the GCF  \r
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document.write( " Factor the inner expression  \r
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document.write( "Now set each factor equal to zero:\r
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document.write( ",  or \r
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document.write( ",  , or Now solve for x in each case\r
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document.write( "Notice we get the solution twice\r
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document.write( "So our solutions are or \r
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document.write( "Notice if we graph  we get\r
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document.write( " \r
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document.write( "and we can see that the graph has roots at and so this verifies our answer.\r
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document.write( "#5\r
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document.write( " | Solved by pluggable solver: Quadratic Formula | \n" );
document.write( "Let's use the quadratic formula to solve for x:
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document.write( " Starting with the general quadratic
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document.write( " the general solution using the quadratic equation is:
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document.write( " So lets solve  (note: since the polynomial does not have an \"x\" term, the 2nd coefficient is zero. In other words, b=0. So that means the polynomial really looks like  notice  , , and  )
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document.write( "  Plug in a=1, b=0, and c=69
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document.write( "  Square 0 to get 0
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document.write( "  Multiply  to get 
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document.write( "  Combine like terms in the radicand (everything under the square root)
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document.write( "  Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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document.write( "  Multiply 2 and 1 to get 2
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document.write( " After simplifying, the quadratic has roots of
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document.write( "  or 
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