document.write( "Question 1182467: find how the circle x²+y²=1 and x²+y²-6x+5=0 touch each other and find the coordinate of the point of contact \n" ); document.write( "
Algebra.Com's Answer #812522 by MathLover1(20855)\"\" \"About 
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\"x%5E2%2By%5E2=1+\"
\n" ); document.write( "\"x%5E2%2By%5E2-6x%2B5=0+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "\"x%5E2%2By%5E2-1+=0\"
\n" ); document.write( "\"x%5E2%2By%5E2-6x%2B5=0\"
\n" ); document.write( "-------------------------------------\r
\n" ); document.write( "\n" ); document.write( " the point of contact will be where\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2-1+=x%5E2%2By%5E2-6x%2B5\".........simplify\r
\n" ); document.write( "\n" ); document.write( "\"cross%28x%5E2%29%2Bcross%28y%5E2%29-1+=cross%28x%5E2%29%2Bcross%28y%5E2%29-6x%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"-1+=-6x%2B5\"
\n" ); document.write( "\"6x+=1%2B5\"
\n" ); document.write( "\"6x+=6\"
\n" ); document.write( "\"x=1\"\r
\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2=1\" ....substitute \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"1%5E2%2By%5E2=1\"
\n" ); document.write( "\"1%2By%5E2=1+\"
\n" ); document.write( "\"y%5E2=1-1\"
\n" ); document.write( "\"y%5E2=0\"
\n" ); document.write( "\"y=0\"\r
\n" ); document.write( "\n" ); document.write( "the point of contact will be at (\"1\",\"0\")\r
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