document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181790>Question 1181790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ou deposit P200 in an account earning 5% compound interest for 3 years. Find the future value and the interest earned for each of the following compounding frequencies. Use the Bankers' Rule for daily compounding.\r<BR>\n" );
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document.write( "Frequency	Future Value	Interest Earned<BR>\n" );
document.write( "Annually:	<BR>\n" );
document.write( "Semiannually:	<BR>\n" );
document.write( "Quarterly:	<BR>\n" );
document.write( "Monthly:	<BR>\n" );
document.write( "Daily: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812488 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> annually is P=200(1+0.05/1)^3=P231.53<BR>\n" );
document.write( "semi is P=200(1+(.05/2))^6, less to compound but more times compounded,=P231.94<BR>\n" );
document.write( "quarterly will be slightly more or P=200(1+(.05/4))^12=P232.15<BR>\n" );
document.write( "monthly is P=200*(1+(.05/12))^36=P232.29 <BR>\n" );
document.write( "Round everything at the end.<BR>\n" );
document.write( "daily use 360 so P=(1+(.05/360))^1080=P232.36<BR>\n" );
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