document.write( "Question 1182451: Let A and B be events with P(A)=1/2, P(B)=1/3 and P(A∩B)=1/4. Find
\n" ); document.write( "i) P(A | B)
\n" ); document.write( "ii) P(B | A)
\n" ); document.write( "iii) P(A U B)
\n" ); document.write( "iv) P(A'| B')
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Algebra.Com's Answer #812461 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Use 12 as the denominator for each probability, since 12 is the least common multiple of 2, 3, and 4.

\n" ); document.write( "Given: P(A) = 6/12; P(B) = 4/12; P(A∩B) = 3/12

\n" ); document.write( "Then
\n" ); document.write( "P(A∩B') = P(A)-P(A∩B) = 6/12-3/12 = 3/12
\n" ); document.write( "P(A'∩B) = P(B)-P(A∩B) = 4/12-3/12 = 1/12

\n" ); document.write( "P(AUB) = P(A)+P(B)-P(A∩B) = 6/12+4/12-3/12 = 7/12
\n" ); document.write( "P(A'∩B') = 1-P(AUB) = 1-7/12 = 5/12

\n" ); document.write( "i) P(A|B) = P(A∩B)/P(A) = (3/12)/(6/12) = 3/6 = 1/2

\n" ); document.write( "ii) P(B|A) = P(A∩B)/P(B) = (3/12)/(4/12) = 3/4

\n" ); document.write( "iii) (from above) P(AUB) = 7/12

\n" ); document.write( "iv) P(A'|B') = P(A'∩B')/P(B') = (5/12)/(1-4/12) = (5/12)/(8/12) = 5/8
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