document.write( "Question 1182336: The average price of a personal computer(PC) is $949. If the computer prices are approximately normally distributed and the population standard deviation is $100, what is the probability that a randomly selected PC costs more than $1200? (Please answer in decimal and round the answer to three decimal places) \n" ); document.write( "
Algebra.Com's Answer #812455 by Theo(13342) You can put this solution on YOUR website! average (mean) is 949 \n" ); document.write( "standard deviation is 100 \n" ); document.write( "you want to find the probability that a randomly selected computer costs more than 1200.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z-score = (x - m) / s \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard deviation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (1200 - 949) / 100 = 2.51\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of a price greater than that would be .0060365747 = .006 rounded to 3 decimal places. \n" ); document.write( " \n" ); document.write( " |