document.write( "Question 1182434:  The length of rectangular solids is four times the width and the height is twice the width.
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document.write( "Find the volume and the length of its diagonal if the total surface area is 198 in2 \n" );
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Algebra.Com's Answer #812444 by ikleyn(52903)    You can put this solution on YOUR website! . \n" ); document.write( "The length of rectangular solids is four times the width and the height is twice the width. \n" ); document.write( "Find the volume and the length of its diagonal if the total surface area is 198 in2 \n" ); document.write( "~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let W be the width. \r\n" ); document.write( "\r\n" ); document.write( "Then the length is 4W and the height is 2W.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The total surface area is 2*(LW + LH + WH) = 2*( (4W)*W + (4W)*(2W) + W*(2W) ) = 2*(4W^2 + 8W^2 + 2W^2) = 28W^2.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus we have this equation to determine W\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 28W^2 = 198 in^2.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It implies\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " W^2 = 198/28 =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Enjoy ( ! )\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do not forget to post your \"THANKS\" to me for my teaching (!)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "  |