document.write( "Question 1182377: Hi
\n" ); document.write( "In a 3 digit number, the units digit is 3 more than the tens digit, and the sum of the digitsis 11 . If the units and hundreds are reversed, the number increases by 99. Find the original number. \r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #812373 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "The number N is written “htu” and has value 100h+10t+u\r
\n" ); document.write( "\n" ); document.write( "The digit reversal info leads to h=t+2
\n" ); document.write( "You are also directly given info that tells you
\n" ); document.write( " u = t+3
\n" ); document.write( " h+t+u = 11\r
\n" ); document.write( "\n" ); document.write( "By substituting, this leads to:
\n" ); document.write( "(t+2)+t+(t+3) =11
\n" ); document.write( "3t + 5 = 11
\n" ); document.write( "t = 2 ==> u = 5, h = 4\r
\n" ); document.write( "\n" ); document.write( "The number is 425
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