document.write( "Question 1182314: In triangle PQR, P = 50°, PR = 11 and PQ = 9.\r
\n" ); document.write( "\n" ); document.write( "a) Show that there are two possible measures of PQR\r
\n" ); document.write( "\n" ); document.write( "b) Sketch triangle PQR for each case\r
\n" ); document.write( "\n" ); document.write( "c)For each case, find: i) the measure of QPR , ii) the area of the triangle, iii) the perimeter of the triangle.
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Algebra.Com's Answer #812365 by MathTherapy(10555)\"\" \"About 
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In triangle PQR, P = 50°, PR = 11 and PQ = 9.\r
\n" ); document.write( "\n" ); document.write( "a) Show that there are two possible measures of PQR\r
\n" ); document.write( "\n" ); document.write( "b) Sketch triangle PQR for each case\r
\n" ); document.write( "\n" ); document.write( "c)For each case, find: i) the measure of QPR , ii) the area of the triangle, iii) the perimeter of the triangle.
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Is measure of PQR referring to ∡PQR? If so, don't you think you need to state that? 
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document.write( "If so and measure of QPR refers to ∡QPR, which is the same as ∡P, wasn't that given?
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document.write( "a) Use the 2 given sides, the included angle, and Law of Cosines to find side p (same as side QR).
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document.write( "   This should be around 8.644539 units. Then use the Law of Sines to find ∡Q, which should be approximately 78.47o.   
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document.write( "   With ∡s P and Q being 50o, and 78.47o, respectively, ∡R is then 51.53o.
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document.write( "   Note that ∡Q, being 78.47o can also measure 101.53o since its reference angle measures that, in the 2nd quadrant.
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document.write( "   With ∡Q being 101.53o, ∡P, 50o, then ∡R becomes 28.47o. This proves that ∡Q (same as ∡PQR) can have 2 measures. 
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document.write( "   This also means that ∆PQR can either be ACUTE or OBTUSE.
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document.write( "   Note that with 2 sides and an INCLUDED angle given, the requested AREA of this NON-RIGHT triangle can be found
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document.write( "   by using the formula: \"highlight_green%28matrix%281%2C3%2C+Area%2C+%22=%22%2C+%281%2F2%29ab%2ASin+%28C%29%29%29\", which in this case would be: \"highlight_green%28matrix%281%2C3%2C+Area%2C+%22=%22%2C+%281%2F2%29qr%2Asin+%28P%29%29%29\"
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document.write( "   You should now be able to answer the other questions. \n" );
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