document.write( "Question 1182366: A man runs 200 yards East and then turns around and runs 50 yards West in 35 seconds what is the man's average velocity for this trip ?
\n" ); document.write( "I added the yards 200 yard+50 yard = 250 yards then divided 250/35 . Is this correct
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Algebra.Com's Answer #812364 by ikleyn(52946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "            This problem  TEACHES  you  to distinct  between  average velocity  and  average speed \r
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\n" ); document.write( "\n" ); document.write( "            (which in this problem is the same as average rate).\r
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\n" ); document.write( "\n" ); document.write( "To calculate average speed  (or average rate),  you should take the total traveled distance and divide it by the full spent traveled time.\r
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\n" ); document.write( "\n" ); document.write( "But  THIS  PROBLEM  asks about the average velocity.\r
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\n" ); document.write( "\n" ); document.write( "Velocity is the vector,  in distinct of speed and of rate.\r
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\n" ); document.write( "\n" ); document.write( "To calculate average velocity,  you should take the  displacement vector  and divide it by the full spent traveled time.\r
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\n" ); document.write( "\n" ); document.write( "        In this problem,  the displacement is  THE  DIFFERENCE   200 yards   MINUS   50 yards = 200 - 50 = 150 yards\r
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\n" ); document.write( "\n" ); document.write( "                                and you should divide it by  35  seconds.\r
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\n" ); document.write( "\n" ); document.write( "So,  the average velocity magnitude is   \"%28200-50%29%2F35\" = \"150%2F35\" = 4.286 yards per second.             ANSWER
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\n" ); document.write( "\n" ); document.write( "Solved and explained.\r
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